/* * Copyright (c) 2002 Apple Computer, Inc. All rights reserved. * * @APPLE_LICENSE_HEADER_START@ * * Copyright (c) 1999-2003 Apple Computer, Inc. All Rights Reserved. * * This file contains Original Code and/or Modifications of Original Code * as defined in and that are subject to the Apple Public Source License * Version 2.0 (the 'License'). You may not use this file except in * compliance with the License. Please obtain a copy of the License at * http://www.opensource.apple.com/apsl/ and read it before using this * file. * * The Original Code and all software distributed under the License are * distributed on an 'AS IS' basis, WITHOUT WARRANTY OF ANY KIND, EITHER * EXPRESS OR IMPLIED, AND APPLE HEREBY DISCLAIMS ALL SUCH WARRANTIES, * INCLUDING WITHOUT LIMITATION, ANY WARRANTIES OF MERCHANTABILITY, * FITNESS FOR A PARTICULAR PURPOSE, QUIET ENJOYMENT OR NON-INFRINGEMENT. * Please see the License for the specific language governing rights and * limitations under the License. * * @APPLE_LICENSE_HEADER_END@ */ #define ASSEMBLER #include #undef ASSEMBLER // ***************** // * S T R N C A T * // ***************** // // char* strncat(char *dst, const char *src, size_t count); // // We optimize the move by doing it word parallel. This introduces // a complication: if we blindly did word load/stores until finding // a 0, we might get a spurious page fault by touching bytes past it. // To avoid this, we never do a "lwz" that crosses a page boundary, // or store extra bytes. // // The test for 0s relies on the following inobvious but very efficient // word-parallel test: // x = dataWord + 0xFEFEFEFF // y = ~dataWord & 0x80808080 // if (x & y) == 0 then no zero found // The test maps any non-zero byte to zero, and any zero byte to 0x80, // with one exception: 0x01 bytes preceeding the first zero are also // mapped to 0x80. // // Note that "count" refers to the max number of bytes to _append_. // There is no limit to the number of bytes we will scan looking for // the end of the "dst" string. .text .globl EXT(strncat) .align 5 LEXT(strncat) andi. r0,r3,3 // is dst aligned? dcbtst 0,r3 // touch in dst lis r6,hi16(0xFEFEFEFF) // start to load magic constants lis r7,hi16(0x80808080) dcbt 0,r4 // touch in source ori r6,r6,lo16(0xFEFEFEFF) ori r7,r7,lo16(0x80808080) mr r9,r3 // use r9 for dest ptr (must return r3 intact) beq Lword0loop // dest is aligned subfic r0,r0,4 // r0 <- #bytes to word align dest mtctr r0 // set up byte loop // Loop over bytes looking for 0-byte marking end of dest, until dest is // word aligned. // r4 = source ptr (unaligned) // r5 = count (unchanged so far) // r6 = 0xFEFEFEFF // r7 = 0x80808080 // r9 = dest ptr (unaligned) // ctr = byte count Lbyte0loop: lbz r8,0(r9) // r8 <- next dest byte addi r9,r9,1 cmpwi r8,0 // test for 0 bdnzf eq,Lbyte0loop // loop until (ctr==0) | (r8==0) bne Lword0loop // haven't found 0, so enter word-aligned loop andi. r0,r4,3 // is source aligned? subi r9,r9,1 // point to the 0-byte we just stored beq Laligned // source is already aligned subfic r0,r0,4 // r0 <- #bytes to word align source b Lbyteloop // must align source // Loop over words looking for 0-byte marking end of dest. // r4 = source ptr (unaligned) // r5 = count (unchanged so far) // r6 = 0xFEFEFEFF // r7 = 0x80808080 // r9 = dest ptr (word aligned) .align 5 // align inner loops for speed Lword0loop: lwz r8,0(r9) // r8 <- next dest word addi r9,r9,4 add r10,r8,r6 // r10 <- word + 0xFEFEFEFF andc r12,r7,r8 // r12 <- ~word & 0x80808080 and. r11,r10,r12 // r11 <- nonzero iff word has a 0-byte beq Lword0loop // loop until 0 found slwi r10,r8,7 // move 0x01 bits (false hits) into 0x80 position andi. r0,r4,3 // is source aligned? andc r11,r11,r10 // mask out false hits subi r9,r9,4 // back up r9 to the start of the word cntlzw r10,r11 // find 0 byte (r0 = 0, 8, 16, or 24) srwi r10,r10,3 // now r10 = 0, 1, 2, or 3 add r9,r9,r10 // now r9 points to the 0-byte in dest beq Laligned // skip if source already aligned subfic r0,r0,4 // r0 <- #bytes to word align source // Copy min(r0,r5) bytes, until 0-byte. // r0 = #bytes we propose to copy (NOTE: must be >0) // r4 = source ptr (unaligned) // r5 = length remaining in buffer (may be 0) // r6 = 0xFEFEFEFF // r7 = 0x80808080 // r9 = dest ptr (unaligned) Lbyteloop: cmpwi r5,0 // buffer empty? (note: unsigned) beq-- L0notfound // buffer full but 0 not found lbz r8,0(r4) // r8 <- next source byte subic. r0,r0,1 // decrement count of bytes to move addi r4,r4,1 subi r5,r5,1 // decrement buffer length remaining stb r8,0(r9) // pack into dest cmpwi cr1,r8,0 // 0-byte? addi r9,r9,1 beqlr cr1 // byte was 0, so done bne Lbyteloop // r0!=0, source not yet aligned // Source is word aligned. Loop over words until 0-byte found or end // of buffer. // r4 = source ptr (word aligned) // r5 = length remaining in buffer // r6 = 0xFEFEFEFF // r7 = 0x80808080 // r9 = dest ptr (unaligned) Laligned: srwi. r8,r5,2 // get #words in buffer addi r0,r5,1 // if no words, copy rest of buffer beq-- Lbyteloop // fewer than 4 bytes in buffer mtctr r8 // set up word loop count rlwinm r5,r5,0,0x3 // mask buffer length down to leftover bytes b LwordloopEnter // Inner loop: move a word at a time, until one of two conditions: // - a zero byte is found // - end of buffer // At this point, registers are as follows: // r4 = source ptr (word aligned) // r5 = bytes leftover in buffer (0..3) // r6 = 0xFEFEFEFF // r7 = 0x80808080 // r9 = dest ptr (unaligned) // ctr = whole words left in buffer .align 5 // align inner loop, which is 8 words long Lwordloop: stw r8,0(r9) // pack word into destination addi r9,r9,4 LwordloopEnter: lwz r8,0(r4) // r8 <- next 4 source bytes addi r4,r4,4 add r10,r8,r6 // r10 <- word + 0xFEFEFEFF andc r12,r7,r8 // r12 <- ~word & 0x80808080 and. r11,r10,r12 // r11 <- nonzero iff word has a 0-byte bdnzt eq,Lwordloop // loop if ctr!=0 and cr0_eq beq-- LcheckLeftovers // skip if 0-byte not found // Found a 0-byte. Store last word up to and including the 0, a byte at a time. // r8 = last word, known to have a 0-byte // r9 = dest ptr Lstorelastbytes: srwi. r0,r8,24 // right justify next byte and test for 0 slwi r8,r8,8 // shift next byte into position stb r0,0(r9) // pack into dest addi r9,r9,1 bne Lstorelastbytes // loop until 0 stored blr // 0-byte not found while appending words to source. There might be up to // 3 "leftover" bytes to append, hopefully the 0-byte is in there. // r4 = source ptr (past word in r8) // r5 = bytes leftover in buffer (0..3) // r6 = 0xFEFEFEFF // r7 = 0x80808080 // r8 = last word of source, with no 0-byte // r9 = dest ptr (unaligned) LcheckLeftovers: stw r8,0(r9) // store last whole word of source addi r9,r9,4 addi r0,r5,1 // let r5 (not r0) terminate byte loop b Lbyteloop // append last few bytes // 0-byte not found in source. We append a 0 anyway, even though it will // be past the end of the buffer. That's the way it's defined. // r9 = dest ptr L0notfound: li r0,0 stb r0,0(r9) // add a 0, past end of buffer blr